How do I form a oauth2 password-grant request using webwrite [grant_type = "password" ]

Question

Robin Lataire 2019-1-15

1
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/439850-how-do-i-form-a-oauth2-password-grant-request-using-webwrite-grant_type-password

评论： Fritjof Basan 2023-9-5

采纳的回答： Steven Remington

在 MATLAB Online 中打开

How do I request an access token using Oauth2 with the grant_type = "password"

https://www.oauth.com/oauth2-servers/access-tokens/ password-grant/

I have tried:

client_id = 'client_id_FILL';%'YOUR CLIENT ID ';
client_secret = 'client_secret_FILL';%'YOUR CLIENT SECRET ';
url = 'https://your_url/connect/token';
username = 'usernameFILL';
password='passwFILL';
scope = 'scope-FILL';
headerFields = {'Content-type' 'application/x-www-form-urlencoded';'charset' 'UTF-8'};
options = weboptions('HeaderFields', headerFields);
response = webwrite(url,...
'client_id', client_id,...
'client_secret', client_secret,...
'grant_type','password',...
'scope',scope,... 
'username',username,...
'password',password,...
options);

resulting in

Error using readContentFromWebService (line 46)
The server returned the status 400 with message "Bad Request" in response to the request to URL

Problem solved:

the above code is working. In my case, the error originated from server side, where there was an issue with the username and password.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Fritjof Basan 2023-9-5

Worked for me. Thank you for sharing this!

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Steven Remington 2019-1-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/439850-how-do-i-form-a-oauth2-password-grant-request-using-webwrite-grant_type-password#answer_357046

I would look into the link below which forms an oauth2 for google api:

https://www.mathworks.com/matlabcentral/answers/264403-how-can-i-access-an-api-which-requires-oauth-2-0-authorization-such-as-google-apis

The above link shows how the request is formed to construct a weboptions object.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Robin Lataire 2019-1-25

Thanks for the input. I used your above reference to write the code. Meanwhile, the error was solved. The above code is working. In my case, the error originated from server side, where there was an issue with the username and password.

请先登录，再进行评论。