Problem passing function to lsqnonlin with costant parameters
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Hello, i have this function to pass to lsqnonlin :
[val,Jac] = myfunction(x,par1,par2,par3)
my function computes already the Jacobian that im planning to pass to slqnonlin and is essential.
x is the optimization variable and par1,par2... are constant parameters required to evaluate the function and are computed separately.
The problem then is how i declare x as the only optimization variable?
I can't use function handle otherwise i would lose my multi ouput;
I can't declare par1,par2,... as globals cause myfunction has parallelization in it;
I could pass the code to evaluate pars into myfunction but it would add not necessary heavy computation into each iteration of lsqnonlin which i'd like to avoid;
Any other ideas? Thank you
采纳的回答
par1=______;
par2=______;
par3=______;
lsqnonlin(@(x) myfunction(x,par1,par2,par3), __________);
See also Passing Extra Parameters.
6 个评论
Eugenio Grabovic
2019-1-15
编辑：Eugenio Grabovic
2019-1-15
Eugenio Grabovic
2019-1-15
编辑：Eugenio Grabovic
2019-1-15
Matt J
2019-1-18
There shouldn‘t have been issues with a 2nd output argument either way. I’d have to see your complete code to say why there was.
Eze Far
2023-7-4
Hi, will this "lsqnonlin(@(x) myfunction(x,par1,par2,par3), __________);" also make use of the second output of "myfunction", i.e. Jac?
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