I am getting an error as "Operands to the || and && operators must be convertible to logical scalar values. Error in xd (line 8) if (t>=t1)&&(t<t2)".

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Chiliveri Vinod 2019-1-17

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编辑： madhan ravi 2019-1-17

my code is

t1 = 0;
t2 = 10;
t3 = 20;
t4 = 30;
t = 0:50;
if (t>=t1)&&(t<t2)
    r = 0.6;
    if (t>=t2)&&(t<t3)
    r = 0.3;
    if (t>=t3)&&(t<t4)
    r = 0.3;
    if (t>=t4)
    r = 0.6;
    end
    end
    end
end
plot(t,r)

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Answer 1

Omer Yasin Birey 2019-1-17

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编辑：Omer Yasin Birey 2019-1-17

在 MATLAB Online 中打开

You cannot compare a vector t (which is 1x51 double) with a single value for an if statement, with the logical operators. Even if you could, the plot at the end won't give anything. I believe you want to do this.

t1 = 0;
t2 = 10;
t3 = 20;
t4 = 30;
t = 0:50;
r = zeros(length(t),1);
for i = 1:length(t)
    if (t(i)>=t1)&&(t(i)<t2)
            r(i) = 0.6;
    elseif (t(i)>=t2)&&(t(i)<t3)
            r(i) = 0.3;
    elseif (t(i)>=t3)&&(t(i)<t4)
            r(i) = 0.3;
    else 
            r(i) = 0.6;
    end
   
end
plot(t,r)
axis([0 60 0.2 0.7])

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Stephen23 2019-1-17

编辑：Stephen23 2019-1-17

"You cannot compare a vector t (which is 1x51 double) with a single value for an if statement"

Actually you can: comparing a vector against a scalar value is permitted, and providing a non-scalar condition to if is also permitted (but you should read the if documentation very carefully before using this):

>> if [1,2,3]>0, disp('oh, it works!'), end
oh, it works!
>>

Personally I would recommend against non-scalar if or while conditions, but they certainly are possible in MATLAB.

Omer Yasin Birey 2019-1-17

Yes Stephen, you are right. I edited this.

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Answer 2

Stephen23 2019-1-17

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编辑：Stephen23 2019-1-17

Learn to use logical indexing

https://www.mathworks.com/help/matlab/getting-started-with-matlab.html

Logical indexing is a very basic MATLAB concept that will make your code simpler and more efficient:

>> t1 = 0;
>> t2 = 10;
>> t3 = 20;
>> t4 = 30;
>> t = 0:50;
>> r = nan(size(t));
>> r((t>=t1)&(t<t2)) = 0.6;
>> r((t>=t2)&(t<t3)) = 0.3;
>> r((t>=t3)&(t<t4)) = 0.3;
>> r((t>=t4)) = 0.6;
>> plot(t,r)

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Answer 3

madhan ravi 2019-1-17

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编辑：madhan ravi 2019-1-17

在 MATLAB Online 中打开

&& and || for scalars for vectors use & and | , logical indexing is efficient:

t1 = 0;
t2 = 10;
t3 = 20;
t4 = 30;
t = 0:50;
r = zeros(size(t));
id1=(t>=t1)&(t<t2)|(t>=t4);
r(id1)=0.6
id2=(t>=t2)&(t<t3);
r(id2) = 0.3;
id3=(t>=t3)&(t<t4)
r(id3) = 0.3;
plot(t,r)
axis([0 60 0 1])