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how to search about a matrix in a cell?

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Sarah A
Sarah A 2019-1-19
评论： Sarah A 2019-1-19
Hello,
Suppose that I have the cell matrix A which contains the following elements:
A={
[0;0] [0;1]
[1;0] [0;0]
}
So I want to use a line of code that can count how many [0;0] are in each row ?
Regards,

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采纳的回答

Guillaume
Guillaume 2019-1-19
编辑：Guillaume 2019-1-19
it's always a good idea to give the result you expect for your example to avoid ambiguity.
A={
[0;0] [0;1]
[1;0] [0;0]
}
sum(cellfun(@(x) isequal(x, [0;0]), A), 2)
results in
ans =
1
1
count of [0;0] in each row.

更多回答（1 个）

madhan ravi
madhan ravi 2019-1-19
编辑：madhan ravi 2019-1-19
Sarah's (OP) example:
A={ ...
[0;0] [0;1]
[1;0] [0;0]
};
counts=nnz(~cellfun(@any,A))
Gives:
counts =
2
Stephen's example:
A={[0;0] [0;1] [1;0] [0;0] [0;0]};
counts=nnz(~cellfun(@any,A))
Gives:
counts =
3
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Sarah A
Sarah A 2019-1-19
Yes this code work with me:
A={ ...
[0;0] [0;1]
[1;0] [0;0]
};
counts=nnz(~cellfun(@any,A))
but what if I want to count how many [0;0] in each row? how many [0;1] in each row? how many [1;1] in each row?

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