Legend of graph doesn't match plot color and style

Question

Kevin Navarro 2019-1-20

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/440620-legend-of-graph-doesn-t-match-plot-color-and-style

评论： Star Strider 2019-1-20

Hello,

I have been looking for a way to match my legend color and characters to what is plotted on the graph. For some reason after the first two legend values, the legend ignores the color and icon that has been plotted and just recycles the second red dotted value for the rest of the plots. How would I get the legend to match the plot?

figure(2)
H=4;
t=0;
omega=2*pi/10;
omegat=omega*t;
kx=-2*pi:.1:2*pi;
eta=H/2*cos((kx)+(omegat));
etaH=eta/H;
plot(kx,etaH)
xlabel('Dimentionless Distance kx')
ylabel('Dimentionless Elevation \eta/H')
% t=0
t=0;
omegat0=omega*t;
hold on
plot(kx,omegat0,'r.')
% t=1
hold on
t=1;
omegat1=omega*t;
plot(kx,omegat1,'y.')
% t=2
hold on
t=2;
omegat2=omega*t;
plot(kx,omegat2,'g.')
% t=3
hold on
t=3;
omegat3=omega*t;
plot(kx,omegat3,'m.')
% Legend
legend('\eta/H as a function of kx', '\omegat at t=0','\omegat at t=1','\omegat at t=2','\omegat at t=3')

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Answer 1

Star Strider 2019-1-20

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/440620-legend-of-graph-doesn-t-match-plot-color-and-style#answer_357230

在 MATLAB Online 中打开

You can plot an independent variable aganst a dependentent variable constant, however you will end up with the problem you are seeing. Multiplying the constant by a ones vector solves the problem:

hold all
plot(kx,omegat0*ones(size(kx)),'r.')
% t=1
t=1;
omegat1=omega*t;
plot(kx,omegat1*ones(size(kx)),'y.')
% t=2
t=2;
omegat2=omega*t;
plot(kx,omegat2*ones(size(kx)),'g.')
% t=3
t=3;
omegat3=omega*t;
plot(kx,omegat3*ones(size(kx)),'m.')
hold off