Finding an average of sample point in an array with irregular intervals

Av2 = cell(4,4);
% I2 = rand(20,20,20);
for i = 1:4 
    for j = 1:4
        
        Av2{i,j}=mean([I2(1:i:10),I2(2:j:10)]);
    end
end
meanWind = mean(cellfun(@(c) c, Av2(:)));

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Omer Yasin Birey 2019-1-23

在 MATLAB Online 中打开

Of course, it is possible. You are changing the columns here so I assumed you want to calculate the mean of columns. You can use the code below for mean of columns. Else if you want to take mean of rows use the second code.

Av2 = zeros(4,4);
% I2 = rand(20,20,20);
for i = 1:4 
    for j = 1:4
        
        Av2(i,j)=mean([I2(1:i:10),I2(2:j:10)]);
    end
end
meanOfEachColumns = mean(Av2',2);

if you want the mean of rows

Av2 = zeros(4,4);
% I2 = rand(20,20,20);
for i = 1:4 
    for j = 1:4
        
        Av2(i,j)=mean([I2(1:i:10),I2(2:j:10)]);
    end
end
meanOfEachColumns = mean(Av2,2);

Pavel Kutsenko 2019-1-23

But i dont really have rows or columns, i just have an array of numbers. So if I use this code with I2=[1:10] i get (5.6, 5.3, 5.6, 5.4) as my means and i am looking for (2,3,5,8)

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