find array in cell using cellfun

Question

NA 2019-1-23

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/441058-find-array-in-cell-using-cellfun

回答： Andrei Bobrov 2019-1-23

I have

A = {[1,2,4],[2,3,4],[1,2,5]};
mes_in=[12,18,15,14,13]
B=[1  2;...
1;... 
4;...
1;...
5;...
1;...
3;...
2;...
4;...
2;...
5;...
2;...
4;...
3]
mes_between=[12;12.2;13;13.8;9;9.1;4;4.2;5;5.8;6;6.8;7;7.8]

I want calulate:

for

A=[1,2,4]
mes_in(1)=12=A{1}(1) , mes_in(2)=18=A{1}(2), mes_in(4)=14=A{1}(4)

start from first element in A: 1

mes_in(1)=12,
F = @(v)find(any(v==B(:,1),2)&~any(v==B(:,2),2));
C = cellfun(F,A,'uni',0) % I can calculate index 5
mes_between(5)=9 
mes_true=mes_in(1)-mes_between(5)=12-9=3

start from second element in A: 2

mes_true=mes_in(2)-mes_between(7)-mes_between(11)=18-4-6=8

start from second element in A: 4

mes_true=mes_in(4)-mes_between(14)=14-7.8=6.2

I use this one but it is not working

F = @(v)find(any(v==B(:,1),2)&~any(v==B(:,2),2));
C = cellfun(F,A,'uni',0)
mes_true=cellfun(@(n,i) c-mes_between(i),mes_in,C,'uni' ,0);    	    	 

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NA 2019-1-23

编辑：NA 2019-1-23

在 MATLAB Online 中打开

F = @(v)find(any(v==B(:,1),2)&~any(v==B(:,2),2));
C = cellfun(F,A,'uni',0)

gives C=[5;7;11;14] for A{1}.

I want to seperate [5;7;11;14], as such

mes_true=mes_in(1)-mes_between(5)=12-9=3  
mes_true=mes_in(2)-mes_between(7)-mes_between(11)=18-4-6=8
mes_true=mes_in(4)-mes_between(14)=14-7.8=6.2

Stephen23 2019-1-23

See also earlier related thread:

https://www.mathworks.com/matlabcentral/answers/439821-find-array-inside-a-cell

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Answer 1

Andrei Bobrov 2019-1-23

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/441058-find-array-in-cell-using-cellfun#answer_357658

A = {[1,2,4],[2,3,4],[1,2,5]};
mes_in=[12,18,15,14,13];
B=[1  2;...
   2  1;... 
   1  4;...
   4  1;...
   1  5;...
   5  1;...
   2  3;...
   3  2;...
   2  4;...
   4  2;...
   2  5;...
   5  2;...
   3  4;...
   4  3];
mes_between=[12;12.2;13;13.8;9;9.1;4;4.2;5;5.8;6;6.8;7;7.8];
out = cellfun(@(x)fun(x,B,mes_in(:),mes_between(:),(1:size(B,1))'),A,'un',0);
function out = fun(x,B,mes_in,mes_between,k)
    b = x(:)' == permute(B,[1,3,2]);
    lo = any(b,2);
    p = k.*b(:,:,1);
    [~,jj,v] = find(p(lo(:,:,1)&~lo(:,:,2),:));
    out = mes_in(x) - accumarray(jj,mes_between(v),[numel(x),1]);
end