Multiplications inside a cell array

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Ishita Trivedi
Ishita Trivedi 2019-1-23
评论： Guillaume 2019-1-23
Capture.PNG
Hi everyone,
The above 4x12 is a cell array. Each cell contains numbers. What I want to do next is matrix multiplication between all elements of row 2 with row 4. So, (1,2)*(4,2). This will give a 33by33 matrix. Next, I want to store it in a new variable. But since this is a cell structure I am not able to do it and need help.
How can I concatenate it? Or should i convert the cell array to something else to make my life easier?
Thank you for your help.

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采纳的回答

Kevin Phung
Kevin Phung 2019-1-23
use cell brackets to access contents of the cell array.
so if c is your 4x12 cell array, then c{2,1} would retun the array inside instead of the cell.

更多回答（1 个）

Guillaume
Guillaume 2019-1-23
编辑：Guillaume 2019-1-23
result = cellfun(@times, yourcellarray(1, :), yourcellarray(4, :), 'UniformOutput', true)
will create a 1x12 cell array of 33x33 matrices. The same implemented as a loop:
result = cell(1, size(yourcellarray, 2));
for idx = 1:size(yourcellarray, 2)
result{idx} = yourcellarray{1, idx} .* yourcellarray{4, idx};
end
If you want a 33x33x12 matrix after that:
m = cat(3, result{:})
edit: got the wrong rows
edit again: and messed up the 'UniformOutput'
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Ishita Trivedi
Ishita Trivedi 2019-1-23
I did end up using the loop but I would like to get more comfortable with the cell function.
As for the other answer, my for loop wasn't working because I wasn't using the curly braces - which makes sense since i needed to access the contents of the cell. I didn't explicity post what i had already tried but that was my error in the for loop. I guess it was luck but I thought Kevin figured i am having trouble because I am not accesing the contents of the cell correctly - which is true and is also clear in your answer. Thank you for you help.
Guillaume
Guillaume 2019-1-23
No problem. Is cellfun clearer now?

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