Error in following matlab code.

Error in following codes
for i = 1:12
if i == 12
x1 = 9
end
x1 = [1];
x2 = [3];
if i == 1
x1 = 2
else
x1(i) = x1(i-1) - x2;
end
x = [x1 x2]
end
When i run it it shows following error please help me to solve error.
Array indices must be positive integers or logical values.

3 个评论

What is your desired result ? Give an example.
I want 12 values of x1 and x2 where current x1 from i = 2 to 12 will calculate using x1(i) = x(i-1) -x2.
Yes, but did Star's answer below solve your problem or not? Did you even try it?

请先登录,再进行评论。

回答(1 个)

The error comes from your current calculation of ‘x1’ as:
x1(i) = x1(i-1) - x2;
In the first iteration,i=1 so (i-1)=0. In MATLAB, indices are integers greater than 0, or logical values.
I am not certain this ‘corrected’ version of your code creates the values for ‘x’ that you want. However, it has the virtue of running without error:
for i = 1:12
if i == 12
x1(i) = 9;
end
x1(i) = [1];
x2 = [3];
if i == 1
x1(i) = 2;
else
x1(i+1) = x1(i) - x2;
end
x(i,:) = [x1(i) x2];
end
Experiment to get the result you want.

类别

帮助中心File Exchange 中查找有关 Logical 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by