Vectorized method to find the number of consecutive 1s from the left of an array

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Dang Manh Truong
Dang Manh Truong 2019-1-27
评论： madhan ravi 2019-1-27
Hi, I want to find the number of consecutive 1s from the left of an array (a binary array). For example, if I have A = [1 1 1 0 1 0 0 0 1 1] then the result would be 3 because there are 3 consecutive 1s from the left. Another example: A = [1 0 1 1 1 1 1] then the result would be 1. Or A = [0 1 1 1 0 0 1 0 1], the result would be 0.
I can write this in for loop, however I do not know how to vectorize this part. I really need it for my code so that it might run faster.
Please help me, thank you very much.
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madhan ravi
madhan ravi 2019-1-27
编辑：madhan ravi 2019-1-27
idx=find(diff(A));
if A(1)==0
Result=0
elseif all(A)
Result=numel(A)
else
Result=idx(1)
end

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