Array Indexing Question MATLAB

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Hi I need help with a problem I am to take a 600x800x3 image and assign rid positions so that the first 100x100x3 is one square in position (1,1) and there will be 48 such squares. I am to make the specific square inputed into the function eg (1,1) would be the top left square of the image and set the entire square to black then call this function on a script file with nested loops to repeat this for the other 48 squares

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Addy 2019-1-28

编辑：Addy 2019-1-28

Kind of hard to follow. Could you post the sample data? and the code you tried?

asdf asdf 2019-1-28

So pretty much theres an image 600x800x3 and imagine it being split into 48 squares of size 100x100x3 each and these squares should have grid positions eg the top left square is (1,1) and the bottom right will be (6,8) the output of this function should be the image but now with a square (100x100x3) set to black so now the top left of the image is black. This function should called in a script file using nested loops with a 0.1 s pause showing the change. So pretty much the original image will start getting chopped off row by row going to black

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Answer 1

Rik 2019-1-28

在 MATLAB Online 中打开

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It is not the most beautiful code, but it works:

clc
figure(1),clf(1)
%get the default image
image;ax=get(gcf,'Children');
IM=get(ax,'Children');IM=get(IM,'CData');
c_ax=[0 128];IM=(IM-c_ax(1))/diff(c_ax);IM=uint8(255*IM);
IM=ind2rgb(IM,colormap('winter'));
%resize it to fit actual input
IM=imresize(IM,[600,800]);
imshow(IM)
IM_blocks=mat2cell(IM,...
    100*ones(size(IM,1)/100,1),...
    100*ones(size(IM,2)/100,1),...
    3);
inds=reshape(1:numel(IM_blocks),size(IM_blocks'))';
for n=1:numel(IM_blocks)
    %k=n;%for col-by-col
    k=find(inds==n);
    IM_blocks{k}(:)=0;
    imshow(cell2mat(IM_blocks))
    pause(0.05)
end

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Rik 2019-1-30

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