Fast way to replace elements in a matrix?
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Hi,
for eample I have an a matrix
a =
245 255 255
254 252 255
251 250 239
rules:
find the row index where all 3 numbers in the row are greater than 250.
Is there a faster way to achieve it than do it in a loop?
2 个评论
Note that the question specifically asks for "Fast way to replace elements in a matrix?", and in real code (not just an assignment) logical indexing would likely be used as it avoids the find call:
madhan ravi
2019-1-29
Agree with Stephen , I used find() to explicitly show which row it was.
采纳的回答
madhan ravi
2019-1-29
编辑：madhan ravi
2019-1-29
idx=all(a>250,2) % logical index
L_idx=find(idx) % linear index , gives row number
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