How to generate a coordinate field, compute values for each coordinate and plot the results?

3 次查看（过去 30 天）

显示更早的评论

Christopher Brokmann 2019-1-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/442211-how-to-generate-a-coordinate-field-compute-values-for-each-coordinate-and-plot-the-results

评论： Christopher Brokmann 2019-1-30

采纳的回答： KSSV

在 MATLAB Online 中打开

Hello,

first, i would like to generate a 2D coordinate field from e.g. 0/0 to 0/100, 100/100 and 100/0 with 10 steps, giving 11x11 = 121 coordinates.

My first try is:

for i = 0:10
A(:,1+2*i) = 0:10:100;
A(:,2+2*i) = (i)*10;
end

I don't like this solution, especially if I want to calculate larger fields.....

second, i would like to calculate a value for each coordinate, e.g. value = f(x,y). How can i plot the calculated values with its x,y coordinates in a 3D plot?

I would be very grateful for assistance and possible solutions!

Christopher

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

KSSV 2019-1-30

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/442211-how-to-generate-a-coordinate-field-compute-values-for-each-coordinate-and-plot-the-results#answer_358640

编辑：KSSV 2019-1-30

在 MATLAB Online 中打开

Read about linspace and meshgrid

x = linspace(0,100,11)  ;
y = linspace(0,100,11)  ;
[X,Y] = meshgrid(x,y) ;
Z = X+Y ;
surf(X,Y,Z)

5 个评论
显示 3更早的评论隐藏 3更早的评论

KSSV 2019-1-30

Thats striaght forward.....I have given examples above......as you are using matrices ..read about element by element operations in matrices. https://in.mathworks.com/help/fixedpoint/ref/times.html

Christopher Brokmann 2019-1-30

在 MATLAB Online 中打开

i still have problems to include my function... the only solution i found is with 2 loops, which has the disadvantage of a long run time epsecially for a high number of points for x and y.

x = linspace(0,1,11)  ;
y = linspace(0,1,11)  ;
[X,Y] = meshgrid(x,y) ;
for kk = 1:11
    for nn = 1:11
    Coordinate = [X(kk,nn) Y(kk,nn)];
    
    Z(kk,nn) = f_DeltaWegPunkt(Coordinate,someConstant,...);
    
    end
end