Finding the maximum value in a loop

Question

yasmin 2012-7-23

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Hi all i am trying to find the maximum value in the loop below, can someone please help and explain

for i=1:100
  for angle=-90:90;
  phi=angle*pi/180;
xdata=[sin(sno+(phi))];
ydata=(m_mata(:,:,i))
  R=(corrcoef(xdata,ydata));
        end

example Result from R are

 1.0000    0.6581
 0.6581    1.0000

within the loop above i want to find the maximum value of R(2,1) and also the associated angle that is been used in xdata to give the maximum of R(2,1).

basically I am wanting to find the maximum of R(2,1)and also the associated angle that is been used in xdata to give the maximum of R(2,1),for each time I run for i=1:100, for each loop I want to store the value of R(2,1) and the compare the new value with previous value if the new value is greater for when i=2 then this will be the maximum of R(2,1).If the maximum value of R(2,1) when i=2 is smaller then we use the maximum of R(2,1) when i=1 At the end of the iteration I want to end up with a maximum value of R(2,1) and also the associated phi

I am a bit inexperienced with programming and not sure how to capture this concept and put it in Matlab.

Your help is much appreciated.

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Andrei Bobrov 2012-7-23

how the angle depends of xdata and ydata

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Answer 1

Elizabeth 2012-7-23

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编辑：Elizabeth 2012-7-23

在 MATLAB Online 中打开

I am a little confused on the code you've provided. Perhaps if you were to clarify the problem statement and your objective more clearly I could help me. With what I have understood from you, I have tried to issue you a solution. Here goes nothing, MATLAB code MATLAB code

 i=100; % initialize i
R=zeros(2); %initialize R
        for angle = -90:90
            phi  = angle*pi()/180
            if i==100 % assuming you have x, y data spec when i=100
               R1=corrcoef(xdata,ydata);  
               if R1(2,1)>R(2,1)
                  R=R1; PHA=phi;
                % else R(2,1)>R1(2,1) so R=R;
               end 
            end
        end    
        Rmax=R;  %largest R in Loop
        PHI=PHA; %angle phi associated with largest R

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yasmin 2012-7-23

Thank you Elizabeth

I have tried your code but it is returing the last value of the loop as the largest, which then gives me PHI of 90 which the last angle aswell. What am looking for is to be able to find the largest value of R1(2,1) and the associated angle within

R1=corrcoef(xdata,ydata);

Is it possible to get help with this.

once again thank you very much for your time.

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