Using loop to solve a summation
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Is this correct

m=0
for m=0:1200
x=sum(1/factorial(m))
end
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回答(2 个)
Star Strider
2019-2-7
No, because you need to subscript ‘m’ and sum ‘x’ in each iteration.
However you do not need the loop:
m=0:1200;
x=sum(1./factorial(m))
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Kevin Phung
2019-2-7
编辑:Kevin Phung
2019-2-7
No, you need to increment m with each step and add each partial sum.
This is what you need:
x= 0
for m = 0:1200
x = x + 1/factorial(m(i))
end
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