Root finder matlab code is not displaying result

1 次查看(过去 30 天)
I wrote this code below. It works without errors. However I can't see the result.
It finds the nth root of w, starting from guess g.
w=9;
g=5;
n=2;
function result=findRoot(w,g,n)
if (abs(newGuess-g)<(g*0.0001))
result = newGuess;
disp(result);
else
newGuess = (g - g^n - w) / (n*g^(n-1));
result = findRoot(w, newGuess,n);
disp(result);
end
end
I appreciate any help. Thank you.
  2 个评论
Star Strider
Star Strider 2019-2-10
One problem is that you are calling your function from within the function:
result = findRoot(w, newGuess,n);
This will lead to ‘infinite recursion’, and so no output.
Ceyda Elcin Kaya
Ceyda Elcin Kaya 2019-2-10
编辑:Ceyda Elcin Kaya 2019-2-10
Out of memory. The likely cause is an infinite recursion within the program.
yep the exact problem I'm facing with right now. I will try to find a solution.
edit: i made it i guess. only problem left is that now it displays infinetely
w=9;
g=5;
n=2;
findRoot(w,g,n);
function [result]=findRoot(w,g,n)
newGuess=0;
while(abs(newGuess-g)>g*0.0001)
newGuess = (g - g^n - w) / (n*g^(n-1));
%result = findRoot(w, newGuess,n);
disp(newGuess)
end
result = newGuess;
disp(newGuess);
end

请先登录,再进行评论。

回答(1 个)

Anand Shirke
Anand Shirke 2019-2-10
Maybe the problem is while declaring the function, I would suggest you to declare the function in this way
function [result]=findRoot(w,g,n)
..
.....
end
After saving the code, type in command window :
findRoot(9,5,2)
  1 个评论
Ceyda Elcin Kaya
Ceyda Elcin Kaya 2019-2-10
I did what you say. Now I'm getting a new error.
Function with duplicate name "findRoot" cannot be defined.
But my function is defined.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Programming 的更多信息

产品


版本

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by