Root finder matlab code is not displaying result

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0 个投票

I wrote this code below. It works without errors. However I can't see the result.

It finds the nth root of w, starting from guess g.

w=9;
g=5;
n=2;
function result=findRoot(w,g,n)
 if (abs(newGuess-g)<(g*0.0001))
            result = newGuess;
           disp(result);
 else
    newGuess = (g - g^n - w) / (n*g^(n-1));
           result = findRoot(w, newGuess,n);
            disp(result);   
 end
end

I appreciate any help. Thank you.

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Star Strider 2019-2-10

在 MATLAB Online 中打开

One problem is that you are calling your function from within the function:

result = findRoot(w, newGuess,n);

This will lead to ‘infinite recursion’, and so no output.

Ceyda Elcin Kaya 2019-2-10

编辑：Ceyda Elcin Kaya 2019-2-10

Out of memory. The likely cause is an infinite recursion within the program.

yep the exact problem I'm facing with right now. I will try to find a solution.

edit: i made it i guess. only problem left is that now it displays infinetely

w=9;

g=5;

n=2;

findRoot(w,g,n);

function [result]=findRoot(w,g,n)

newGuess=0;

while(abs(newGuess-g)>g*0.0001)

newGuess = (g - g^n - w) / (n*g^(n-1));

%result = findRoot(w, newGuess,n);

disp(newGuess)

end

result = newGuess;

disp(newGuess);

end

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Answer 1

Anand Shirke 2019-2-10

0 个投票

Maybe the problem is while declaring the function, I would suggest you to declare the function in this way

function [result]=findRoot(w,g,n)

..

.....

end

After saving the code, type in command window :

findRoot(9,5,2)

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Ceyda Elcin Kaya 2019-2-10

I did what you say. Now I'm getting a new error.

Function with duplicate name "findRoot" cannot be defined.

But my function is defined.

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