Numerically Solve for Upperbound on numerical Integral
显示 更早的评论
Hi all,
I am trying to determine how to write the solver code for this example problem. I want to determine the quantitiy s for a given value v such that the following holds true. Although I have provided an explicit integrand here, I am looking for the general code to evaluate this properly with any specified integrand. I just used this one because I am not looking for an analytical solution to this example.
v = 1; % Just an example value
syms s
fun = @(x) x.^x;
vpasolve(integral(fun,x,0,s)==v,s)
The error I get is as follows:
Undefined function or variable 'x'.
vpasolve(integral(fun,x, 0,s)==v,s)
I am sure I am missing something silly. I would appreciate any help you can provide.
采纳的回答
Star Strider
2019-2-12
Try this:
v = 1; % Just an example value
fun = @(x) x.^x;
sval = fzero(@(s)integral(fun,0,s)-v, 1)
Check = integral(fun,0,sval) % Delete Later
produces:
sval =
1.19490700802612
更多回答（1 个）
Walter Roberson
2019-2-12
syms x
vpasolve(int(fun(x), x, 0, s) == v, s)
类别
在 帮助中心 和 File Exchange 中查找有关 Programming 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
