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How to get the values of f at different x
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how can I get f(k+1) reference to values of x, although if I remove range of x, I will get the answer interms of x but I need the values not in variable forms. Here is the code
syms x
P(1)=x^0;
P(2)=x;
for n=1:d
P(n+2)=expand(((2*n+1)/(n+1))*x*P(n+1)-(n/(n+1))*P(n));
end
for k=0:d
a=0;b=1;N=6;
x = a:0.1:b;
f(k+1)= exp(x).*P(k+1); % how can I get this reference to values of x
end
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回答(1 个)
Yasasvi Harish Kumar
2019-2-13
Try using the subs command to substitute values of x in your expression.
syms x
P(1)=x^0;
P(2)=x;
for n=1:d
P(n+2)=expand(((2*n+1)/(n+1))*x*P(n+1)-(n/(n+1))*P(n));
end
for k=0:d
f(k+1)= exp(x).*P(k+1);
a=0;b=1;N=6;
x = a:0.1:b;
t(k+1) = subs(f(k+1),x); % Actual value
end
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