How can I write this C++ script to Matlab?

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onamaewa
onamaewa 2019-2-15
回答： Walter Roberson 2019-2-15
How would you write this C++ script to Matlab?
do k = No_TimeSamples
do i = No_Pixels
SUM_1 = 0
SUM_2 = 0
do j = 1, No_Geophones
delay = R(i, j)/c
ik = round(delay/dt + k)
SUM_1 = SUM_1 + Data(ik, j)
SUM_2 = SUM_2 + Data(ik, j)**2
end
image(i) = image(i) + SUM_1**2 - SUM_2
end
end
  2 个评论
Walter Roberson
Walter Roberson 2019-2-15
编辑：Walter Roberson 2019-2-15
?
That is not C++. It looks like Fortran to me.
Is No_TimeSamples a vector? Should we assume that k is to assume each value stored in No_TimeSamples in turn? Or should we assume that k is to assume only the one value stored in No_TimeSamples? Or should we assume that k is to assume the values from 1 to No_TimeSamples ?
Are you certain that the lower bound for the do j loop should be lower-case L, and not i or 1 ?
onamaewa
onamaewa 2019-2-15
It is a vector.
I have a CSV read into matlab with 10 000 time points, & 32 Sensor Channels.
This code generates an image based on data.
R(i, j) is an array.
Data(ik, j) is an array generated from my csv.
image(i) stores the values that generate the image.

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回答（1 个）

Walter Roberson
Walter Roberson 2019-2-15
for k = No_TimeSamples
for i = No_Pixels
SUM_1 = 0;
SUM_2 = 0;
for j = 1 : No_Geophones
delay = R(i, j)/c;
ik = round(delay/dt + k);
SUM_1 = SUM_1 + Data(ik, j);
SUM_2 = SUM_2 + Data(ik, j).^2;
end
image(i) = image(i) + SUM_1.^2 - SUM_2;
end
end
Note: naming a variable image is not recommended, as it interferes with using the image() display function and confuses readers.

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