Matrix element changing with loop

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I keep getting Dimensions of matrices being concatenated are not consistent error.

for k=1:61

a(:,k)=angle(k,:);

A=[cosd(5) -sind(a); -sind(5) cosd(a)];

x=A\B;

end

I don't get what I am doing wrong

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madhan ravi 2019-2-16

a(k,:)

Answer 1

Stephen23 2019-2-16

编辑：Stephen23 2019-2-16

0 个投票

5 is a scalar. A scalar has size 1x1.

On the second loop iteration a has size Nx2 (we don't know the actual size because you did explain what size angle is).

Then you calculate some trig functions using those 5 and a, giving 1x1 and Nx2 arrays. You then try to concatenate those arrays like this:

[1x1,Nx2;1x1,Nx2]

which is an error if N>1 because then the number of rows are different, which means that those arrays cannot be concatenated together horizontally:

To horizontally concatenate arrays they must have the same number of rows.
To vertically concatenate arrays they must have the same number of columns.

Check the sizes of the arrays that you are trying to concatenate and you will find that one/both of those conditions are not fulfilled.

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Hans123 2019-2-16

I am not 100% sure on how to correct the issue, I just need the matrix to have different values for angle after each iteration how to achieve this? I pasted the code below

angle=-30:1:30;

B= [1200 ; 0 ];

for k=1:61

a(:,k)=angle(k,:);

A=[cosd(5) -sind(a); -sind(5) cosd(a)];

x=A\B;

end

Stephen23 2019-2-17

编辑：Stephen23 2019-2-17

This avoids the error:

a = angle(k);

Only you can decide if this is correct or not.

Also note that you completely discard all x arrays except fot the last one, making your entire for loop superfluous. You might want to use some indexing into an output array.

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Matrix element changing with loop

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