Integration is not evaluated inside a function file
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Hi
Could you please help with code below. It is not clear to me why the integration does not evaluated inside the function file. when I used script it is worked but I need to simplified the process by creating the func file to call it at different steps. The integration is identified for the variable (b) as presented in the code below:
function Fg=Fg(a)
syms b;
f_UHM=b/(-0.181363336688152-0.637631218835414*b)+2.64004309728928;
diff_f_UHM=diff(f_UHM)
a1=a-2.5;
FF=diff_f_UHM*asin(b/a1)
q1=int(FF,0,a1)
F=subs(f_UHM,a1)
Fg=F-(2/pi)*q1
end
采纳的回答
Star Strider
2019-2-18
In the MATLAB Symbolic Math Toolbox, the correct syntax for your int call would be:
q1 = int(FF,b,0,a1)
However, I do not understand the endis call. Is this MATLAB, or is that a typographical error?
4 个评论
Star Strider
2019-2-18
If I run the code and use the vpa function, I get a numeric result:
a = 42; % Supply Scalar Argument
...
q1 = int(FF,b,0,a1)
q1_vpa = vpa(q1)
...
produces:
q1_vpa =
-0.045932121720870913230908902574835
The vpa function will simplify expressions, and if possible, will force a numeric result.
Wazy sky
2019-2-18
Star Strider
2019-2-18
As always, my pleasure!
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