Integration is not evaluated inside a function file

1 次查看（过去 30 天）
Wazy sky
Wazy sky 2019-2-18
评论： Star Strider 2019-2-18
Hi
Could you please help with code below. It is not clear to me why the integration does not evaluated inside the function file. when I used script it is worked but I need to simplified the process by creating the func file to call it at different steps. The integration is identified for the variable (b) as presented in the code below:
function Fg=Fg(a)
syms b;
f_UHM=b/(-0.181363336688152-0.637631218835414*b)+2.64004309728928;
diff_f_UHM=diff(f_UHM)
a1=a-2.5;
FF=diff_f_UHM*asin(b/a1)
q1=int(FF,0,a1)
F=subs(f_UHM,a1)
Fg=F-(2/pi)*q1
end

请先登录，再回答此问题。

采纳的回答

Star Strider
Star Strider 2019-2-18
In the MATLAB Symbolic Math Toolbox, the correct syntax for your int call would be:
q1 = int(FF,b,0,a1)
However, I do not understand the endis call. Is this MATLAB, or is that a typographical error?
  4 个评论
显示 2更早的评论

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by