How do I tell Matlab a loop index is an integer?

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Alexander MacFarlane IV
评论： Alexander MacFarlane IV 2019-2-22
I am perplexed by the fact that niether loop indeces or the number 3 are considered integers.
The script (called WhyNotIntegers)
for i = 1:3
idivide(i,3,'round')
end
produces these errors when run:
Error using idivide>idivide_check (line 66)
At least one argument must belong to an integer class.
Error in idivide (line 42)
idivide_check(a,b);
Error in WhyNotIntegers (line 2)
idivide(i,3,'round')
Error in run (line 96)
evalin('caller', [script ';']);

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采纳的回答

Image Analyst
Image Analyst 2019-2-22
They're doubles that just happen to have integer values. Convert them to integers since that's what idivide wants. Try this:
for k = 1:3
idivide(int32(k), int32(3),'round')
end
  1 个评论
Alexander MacFarlane IV
Alexander MacFarlane IV 2019-2-22
Thanks to both of you for the fast answers.
Stephan got there first, but this told me exactly what I needed to do.
Alex

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更多回答（1 个）

Stephan
Stephan 2019-2-22
编辑：Stephan 2019-2-22
Hi,
by default numbers in Matlab are double. cast them to integer:
int32(i)
Read here:
https://de.mathworks.com/help/releases/R2016b/matlab/matlab_prog/integers.html#f2-54113
Best regards
Stephan

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