how to create logical image from plot in a given scale?

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I want to transform two vectors (x, y) that describe a straight line in the domain (axis([1e-2 7e-2 1e-2 7e-2])) into a logical matrix.
x = linspace (2e-2,6e-2,20);
y = 4e-2 * ones (1,20);
a = [x' y'];
plot (x,y);
axis([1e-2 7e-2 1e-2 7e-2])
I want to get 100*100 matrix, which describe this plot. For that I can creat zeros matrix and then I have to put the ones in the correct place in this matrix. But I don't know where are the correct places.
  2 个评论
Image Analyst
Image Analyst 2019-2-23
It would just be a line since your y values are all the same:
logImage = true(1, length(y));
imshow(logImage);
Do you have some kind of formula for y?
Osama Tabbakh
Osama Tabbakh 2019-2-23
No, y has contant number, because it is a line. But in this way I get a vector. Besides I need a matrix, which hasn't the same size like the vectors, but (100*100).

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Munish Raj
Munish Raj 2019-2-27
Since the line is in the middle of your plot, the row indices of the plot will be the 50th row(middle).
Since the line goes from 0.02 - 0.06 and the axes start from 0.01 and ends at 0.07, your line will start in the 17th position and end at the 83rd position on the x axis.
The following code implements this
im = zeros(100); %Create a 100x100 matrix of zeros
im(50,17:83)=1 % make the necessary elements
I = mat2gray(im);
imshow(I); %Displays the image
  4 个评论
Munish Raj
Munish Raj 2019-2-27
编辑:Munish Raj 2019-2-27
Hello
use your mouse , and drag the corner of the image window to youmake the image as big as tou want it.
Thank you
Osama Tabbakh
Osama Tabbakh 2019-2-27
And do u know how i can do that automatically? I have different shape of lines and i dont want every time to calculate the position of the ones on hand.

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