Converting a 2d vector to a 4d vector

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Basu Sau
Basu Sau 2019-2-25
评论： Basu Sau 2019-2-25
In a machine learning task, I need a 4d single type data to fed for training. But my data is in a 2d format. Would you please show me how to do this conversion.
Input:
for data of 28th row,
val(28,1)=1.5
val(28,2)=2.7
output:
val(:,:,1,28)=1.5
val(:,:,2,28)=2.7
I m looking for your advice in this regard.
Thanks,

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采纳的回答

ANKUR KUMAR
ANKUR KUMAR 2019-2-25
Let's take a random data A
A=randi(10,30,2);
Use permute to change into 4D
B=permute(A,[3,4,2,1]);
Now, B(:,:,2,24) and A(24,2) are same.
>> B(:,:,2,24)==A(24,2)
ans =
logical
1
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ANKUR KUMAR
ANKUR KUMAR 2019-2-25
编辑：ANKUR KUMAR 2019-2-25
First input of permute is the data itself.
Second input is in the row matrix which contains the sequence of dimension you wish to put it.
For example, in B, we have stored first the fourth dimension, then the thrid dimension, followed by second and first.
If we write,
B=permute(A,[3,4,1,2]);
then
>> B(:,:,24,2)==A(24,2)
ans =
logical
1
SIMPLE EXAMPLE
>> A=magic(5)
A =
17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9
>> permute (A,[2,1])
ans =
17 23 4 10 11
24 5 6 12 18
1 7 13 19 25
8 14 20 21 2
15 16 22 3 9
Permute simply changes the dimension as per your input in purmute command.
Basu Sau
Basu Sau 2019-2-25
thanks ankur for a such explainatory comment

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更多回答（1 个）

madhan ravi
madhan ravi 2019-2-25
Aternatively:
[m,n]=size(val);
Val=reshape(val.',1,1,n,m)

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