Converting a 2d vector to a 4d vector
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In a machine learning task, I need a 4d single type data to fed for training. But my data is in a 2d format. Would you please show me how to do this conversion.
Input:
for data of 28th row,
val(28,1)=1.5
val(28,2)=2.7
output:
val(:,:,1,28)=1.5
val(:,:,2,28)=2.7
I m looking for your advice in this regard.
Thanks,
采纳的回答
ANKUR KUMAR
2019-2-25
Let's take a random data A
A=randi(10,30,2);
Use permute to change into 4D
B=permute(A,[3,4,2,1]);
Now, B(:,:,2,24) and A(24,2) are same.
>> B(:,:,2,24)==A(24,2)
ans =
logical
1
3 个评论
Basu Sau
2019-2-25
ANKUR KUMAR
2019-2-25
编辑：ANKUR KUMAR
2019-2-25
First input of permute is the data itself.
Second input is in the row matrix which contains the sequence of dimension you wish to put it.
For example, in B, we have stored first the fourth dimension, then the thrid dimension, followed by second and first.
If we write,
B=permute(A,[3,4,1,2]);
then
>> B(:,:,24,2)==A(24,2)
ans =
logical
1
SIMPLE EXAMPLE
>> A=magic(5)
A =
17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9
>> permute (A,[2,1])
ans =
17 23 4 10 11
24 5 6 12 18
1 7 13 19 25
8 14 20 21 2
15 16 22 3 9
Permute simply changes the dimension as per your input in purmute command.
Basu Sau
2019-2-25
更多回答（1 个）
madhan ravi
2019-2-25
Aternatively:
[m,n]=size(val);
Val=reshape(val.',1,1,n,m)
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