How to replace variable name in function handle?

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Kalore Shubham Arun
评论： Marco Aurélio 2024-7-9
I have a function handle as given below
f = @(x1,x2) x1*x2
and I want to change variable name to
f = @(x) x(1)*x(2)
Please help me
Thanks
PS: The function is just for illustration purpose
  1 个评论
Marco Aurélio
Marco Aurélio 2024-7-9
Hello Matlab mate.
I think you must redefine de function handle just rewriting like this:
f=@(x) prod(x);

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采纳的回答

Stephan
Stephan 2019-2-25
编辑：Stephan 2019-2-25
Hi,
for me this worked:
f = @(x1,x2) x1*x2
f = string(char(f));
f = replace(f,"@(x1,x2)","@(x)");
f = replace(f,["x1","x2"],["x(1)","x(2)"]);
f = str2func(f)
result is:
f =
function_handle with value:
@(x1,x2)x1*x2
f =
function_handle with value:
@(x)x(1)*x(2)
Best regards
Stephan
  2 个评论
madhan ravi
madhan ravi 2019-2-25
编辑：madhan ravi 2019-2-25
stephen what if there are 100 inputs to the function handle? it would be not a good idea
Stephan
Stephan 2019-2-25
编辑：Stephan 2019-2-25
You are right. But i think this function is worth to be shown here as an alternative for small examples. Maybe it is not the best / most efficient solution here. Yours is pretty nice - but the OP asked for how to replace variable names in a function handle - this is what i was answering to.

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更多回答（1 个）

madhan ravi
madhan ravi 2019-2-25
Instead of converting it to your later need convert the vector as comma separated list using num2cell():
x=rand(1,2); % example vector
X=num2cell(x);
f(X{:}) % pass the vector all at once

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