How can I convert a double array into a timestamp array?

2019 2 26
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更新时间：2019 3 11
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I have an array of double like:
ora: [737426.687937060 737426.687937141 737426.687937176 etc....]
I want to get an array like:
time:[16:30:37:762 16:30:37:769 16:30:37:772]
How can i do??

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Stephan
Stephan 2019-2-26
编辑：Stephan 2019-2-26

2 个投票

Hi,
use:
B = datestr(A, 'HH:MM:SS.FFF')
B =
3×12 char array
'16:30:37.762'
'16:30:37.769'
'16:30:37.772'
to get it as datestring - or (better):
C = datetime(datestr(A, 'HH:MM:SS.FFF'),'InputFormat','HH:mm:ss.SSS','Format','HH:mm:ss.SSS')
C =
3×1 datetime array
16:30:37.762
16:30:37.769
16:30:37.772
to get it as datetime-type.
Best regards
Stephan

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Steven Lord
Steven Lord 2019-2-26
There's no need to take a detour through datestr to get these as a datetime array.
A = [737426.687937060 737426.687937141 737426.687937176 ]
D = datetime(A, 'ConvertFrom', 'datenum', 'Format', 'HH:mm:ss.SSS')
Alternately if you want them as a duration (time after midnight) you can do this using dateshift.
D2 = D - dateshift(D, 'start', 'day');
D2.Format = 'hh:mm:ss.SSS'
Peter Perkins
Peter Perkins 2019-3-11
Alternatively, timeofday(D) would also convert to a duration.

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