Okay, now I see the problem you're experiencing, I think. Since this is a bit more technical I'm moving this from the comments of Sayyed Ahmad's Answer into its own Answer.
randn is most likely going to return numbers between say -3 and +3. Instead I'm going to generate some sample data that covers more of the region.
x = randi([0 180], 1000, 1);
data = [x; 180-x];
Now I'll choose some symmetric bins and make the histogram. You might expect this to make a symmetric histogram but it doesn't.
edges = 0:10:180;
h = histogram(data, edges);
So why isn't the histogram symmetric? Each bin except the last contains its left edge but not its right (the last bin contains both edges.) This means a value of 170 in data is part of the last bin in the histogram h (that's the left edge of that last bin.) However a value of 10 in data is not part of the first bin in h (it's the right edge of the first bin and the left edge of the second so it is in the second bin.) To handle this, you could either offset the bin edges so no data value falls exactly on an edge:
edges2 = [-0.5:10:89.5 90.5:10:180.5];
figure;
h2 = histogram(data, edges2);
Or, since my data contains only integer values, use the BinMethod that puts each integer in its own bin.
figure
h3 = histogram(data, 'BinMethod', 'integers');
