0 个投票

Hi, I have the following code that I need to vectorize to compute faster:
Here,
neq = 3197;
length(K1) = 152;
d1 is such d1{1,i} = 3197 by 1;
delNonZero = 152 by 1;
cd = zeros(neq,neq);
for i = 1:length(K1)
for j = 1:length(K1)
cd =cd+ d1{1,i}*d1{1,j}'*mean([delNonZero(i) delNonZero(j)]);
end
end

4 个评论
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Bob Thompson
Bob Thompson 2019-2-28
By 'vectorize' are you asking for us to help you remove one or more of the loops, or are you asking to help you multiply your large arrays together within the loops?
Hi Bob, I just want it to compute faster. Possibly by eliminating for loops. Sorry for the confusion.
Bob Thompson
Bob Thompson 2019-2-28
Got it. I am not an expert in those things, so hopefully somebody else can offer you a better solution. I will say that I don't know if you can eliminate the loops because of your desire to look at just a few elements at a time, rather than just looking at entire rows or the like.
Hi Bob, thank you for your time. I would wait for a solution while trying by myself.

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 采纳的回答

Jos (10584)
Jos (10584) 2019-2-28
编辑：Jos (10584) 2019-2-28

0 个投票

Some suggestions:
  • replace mean(A,B) by (A+B)/2
  • you can have j run from i to length(K1), since everything seems symmetric (unless there are complex numbers involved):
for i = 1:..
cd = cd + d1{i,1}*d1{i,1}'*delNonZero(i) ;
for j = i+1: ..
cd = cd + 2*d1{i,1}*d1{j,1}'*(delNonZero(i)+delNonZero(j))/2; % you can remove the 2's !!
end
end
  • do not use the function CD as avariable name ...

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