multiplying/dividing matrices that contain string variables and NaN

1 次查看(过去 30 天)
Dear all
I have
I have
A= [
29 1;
27 4;
31 0;
28 3;
25 5;
]
and
B={'id1' 'id2' 'id3' 'id4'
[0.4607] [0.4400] [ 0.9167] [0.8701]
[0.4400] [0.4432] [ NaN] [ 0.8808]
[0.4432] [ 0.4419] [ 0.8808] [ 0.8809]
[0.4419] [NaN] [ 0.8809] [ 0.9156]
[0.4607] [0.4547] [ 0.9156] [ 0.9039]
}
and
A1=A(:,1)
And I want to calculate
sum(A.*B(:,1:2),2)/A1
sum(A.*B(:,3:4),2)/A1
in one step because my B contains 120 columns and I want to multiply A with every 2 columns of B that is B(:,1:2) B(:,3:4) B(:,5:6)
S0, I am looking something like
sum(A.*[B(:,1:2) B(:,3:4) B(:,5:6) ],2)/A1
thanks

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-7-29
编辑:Azzi Abdelmalek 2012-7-29
a=B(2:end,:)
ind=cellfun(@(x) ~isstr(x),a);b=a;
b(find(ind==0))=num2cell(0)
C=cell2mat(b);
n=size(b,2);D=[];
for k=1:2:n-1
D=[D A.*C(:,k:k+1)]
end
Result=sum(D,2)./A(:,1)
  4 个评论
Sabbas
Sabbas 2012-7-29
编辑:Sabbas 2012-7-29
could someone help me please? I do not know how to do it
thank you very much

请先登录,再进行评论。

更多回答(1 个)

Oleg Komarov
Oleg Komarov 2012-7-29
Using the same approach from my answer to your previous post:
% First extract only the data
Bdata = cell2mat(B(2:end,:));
bsxfun(@rdivide,squeeze(nansum(bsxfun(@times, reshape(Bdata,5,2,[]),A),2)),A(:,1))
  2 个评论
Sabbas
Sabbas 2012-7-29
When I apply the above code I get the following error message
bsxfun(@times, reshape(out2,ll,2,[]),AS)
Error using bsxfun
Non-singleton dimensions of the two input arrays must match each other.
Am I doing something wrong?
thanks
Oleg Komarov
Oleg Komarov 2012-7-30
As should have at least one dimension the same length as the reshaped out2.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by