Write this without a for loop?

2019 3 3
1 个回答
更新时间：2020 11 15
1 次查看（30 天）

0 个投票

for c= delaySamples+1:length(audioVec)
EchoVec(c)=audioVec(c)+z(c-(delaySamples)*EchoGain);
end

4 个评论
显示 2更早的评论 隐藏 2更早的评论

Andrei Bobrov
Andrei Bobrov 2019-3-3
编辑：Andrei Bobrov 2019-3-3
What is z, EchoGain?
Michelle
Michelle 2019-3-3
heres the entire code for my function
function EchoVec=soundEcho(audioVec,Fs,delay,EchoGain)
EchoGain=input('enter how loud echo should be:');
delay=input('enter in a delay value in seconds:');
delaySamples=Fs*delay;
z=[zeros(1,delaySamples),audioVec'];
audioVec(length(delaySamples))=0;
for c= delaySamples+1:length(audioVec)
EchoVec(c)=audioVec(c)+z(c-(delaySamples)*EchoGain);
end
sound(EchoVec,Fs);
end
madhan ravi
madhan ravi 2019-3-3
编辑：madhan ravi 2019-3-3
when a third person runs your code (it is not possible to run) , nobody has the power to know what is in your computer
Walter Roberson
Walter Roberson 2020-11-15
Michelle, if you feel that the question is unclear, then as you are the person who posted the question, you should be the one who clarifies it to make it more clear.

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回答（1 个）

Alex Mcaulley
Alex Mcaulley 2019-3-4

0 个投票

If audioVec is a column array and you ensure that (delaySamples)*EchoGain is a valid index:
c = delaySamples+1:length(audioVec);
EchoVec(delaySamples+1:length(audioVec))=audioVec(delaySamples+1:end)+z(c-(delaySamples)*EchoGain);

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