how to create 1 in zeros matrix, in order to convert oblique line, which's plotted in x and y coordinates

1 次查看（过去 30 天）
Osama Tabbakh
Osama Tabbakh 2019-3-4
回答： Vijaya Lakshmi Chagi 2019-3-13
I have a line, which's rotated in random angle, but I want this line in an image (0-1) that's why I scaled the points (Leiter) in x and y coordinates in this way:
Line =
0.0418 0.0599 0
0.0417 0.0578 0
0.0415 0.0557 0
0.0413 0.0536 0
0.0411 0.0515 0
0.0409 0.0494 0
0.0407 0.0473 0
0.0405 0.0452 0
0.0403 0.0431 0
0.0401 0.0410 0
0.0399 0.0390 0
0.0397 0.0369 0
0.0395 0.0348 0
0.0393 0.0327 0
0.0391 0.0306 0
0.0389 0.0285 0
0.0387 0.0264 0
0.0385 0.0243 0
0.0383 0.0222 0
0.0382 0.0201 0
x_image = round(((((Line(:,1)*100)-1)*(100-1)/(7-1))+1));
y_image = round(((((Line(:,2)*100)-1)*(100-1)/(7-1))+1));
im = zeros(100);
for i = 1:20
im((y_image(i,1)),(x_image(i,1)))=1;
end
but I don't have a line not anymore, but points
could someone help me?

请先登录，再回答此问题。

回答（1 个）

Vijaya Lakshmi Chagi
Hi Osama,
You can try using the interp1 fucntion rather than rounding off the values. This fucntion interpolates the points based on the query points(sampling over the range of x)

类别

在 Help Center 和 File Exchange 中查找有关 Geometric Transformation and Image Registration 的更多信息

标签

产品


版本

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by