how to create 1 in zeros matrix, in order to convert oblique line, which's plotted in x and y coordinates
2 次查看(过去 30 天)
显示 更早的评论
I have a line, which's rotated in random angle, but I want this line in an image (0-1) that's why I scaled the points (Leiter) in x and y coordinates in this way:
Line =
0.0418 0.0599 0
0.0417 0.0578 0
0.0415 0.0557 0
0.0413 0.0536 0
0.0411 0.0515 0
0.0409 0.0494 0
0.0407 0.0473 0
0.0405 0.0452 0
0.0403 0.0431 0
0.0401 0.0410 0
0.0399 0.0390 0
0.0397 0.0369 0
0.0395 0.0348 0
0.0393 0.0327 0
0.0391 0.0306 0
0.0389 0.0285 0
0.0387 0.0264 0
0.0385 0.0243 0
0.0383 0.0222 0
0.0382 0.0201 0
x_image = round(((((Line(:,1)*100)-1)*(100-1)/(7-1))+1));
y_image = round(((((Line(:,2)*100)-1)*(100-1)/(7-1))+1));
im = zeros(100);
for i = 1:20
im((y_image(i,1)),(x_image(i,1)))=1;
end
but I don't have a line not anymore, but points
could someone help me?
0 个评论
回答(1 个)
Vijaya Lakshmi Chagi
2019-3-13
Hi Osama,
You can try using the interp1 fucntion rather than rounding off the values. This fucntion interpolates the points based on the query points(sampling over the range of x)
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Annotations 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!