Trapezium Rule example won't work?
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I do not understand why this code is not working? I am trying to estimate the integral of e^-x2 between x=0 and x=2 using the trapezium rule采纳的回答
Steven Lord
2019-3-4
You're combining a function declaration and a function call.
Call your function something other than trapz because that's already a function in MATLAB. Let's call it IssieTrapz. It takes four input arguments, which I suspect your function accepts in the following order:
function I = IssieTrapz(f, a, b, n)
This is line 1 of your function. It replaces your original line 1. That's the declaration of the IssieTrapz function.
Now when you call IssieTrapz, that's when you specify the function and give values for a, b, and n.
result = IssieTrapz(@(x) exp(-x^2), 0, 2, 10);
2 个评论
Issie
2019-3-4
Steven Lord
2019-3-4
That second line doesn't go inside your function. That's how you call (use) your function. Type it in the Command Window. When you call your function like that, whatever you pass in as the first input argument will be assigned the name f inside your function. So for this call, f is @(x) exp(-x^2).
You could call it a second time with a different function to change what f is. If you called it like this:
result2 = IssieTrapz(@cos, -pi, 2*pi, 42)
f would be @cos for that call to IssieTrapz.
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