How to create stacked histogram with arrays of different length

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Gian Violi
Gian Violi 2019-3-6
编辑： ch_tsai 2023-10-17
Basically I have column arrays with multiple observations, each belonging to a different category but every element has a different lenght. I want to be able to do something like this, whit each color representing a array (or category).4aBSy.png
I tried to concatenate the arrays into a bigger array and then stacking bars but didn't help beacuse of the lenght issue.
  2 个评论
Martin Roth
Martin Roth 2021-10-1
编辑：Martin Roth 2021-10-1
Better late than never. Check if this solution fits for your problem:
% Create dummy data
A=-20+40*rand(500,1);
B=randn(400,1)*20;
Total=[A;B];
Steps=[0,numel(A),numel(B)];
[N,edges,bins] = histcounts(Total);
% Plot stacked histogram
figure;
colors=lines;
hold on
for i=1:length(Steps)-1
histogram(Total(1+Steps(i):end),'BinEdges',edges,'FaceColor',colors(i,:));
hold on
end
ch_tsai
ch_tsai 2023-10-17
编辑：ch_tsai 2023-10-17
I was trying to find a similar function and found this answer. Your code looks good, thank you! I would like to make it more generalized. For example, if there are more than two set of data, in the last part of your for loop, it's better to write in this way.
% Copy from your code--
% Create dummy data
A=-20+40*rand(500,1);
B=randn(400,1)*20;
C=-25+40*rand(500,1);
D=randn(400,1)*10;
Total=[A;B;C;D];
Steps=[0,numel(A),numel(B),numel(C),numel(D)];
[N,edges,bins] = histcounts(Total);
% Plot stacked histogram
figure;
colors=lines;
hold on
for i=1:length(Steps)-1
histogram(Total(1+sum(Steps(1:i)):end),'BinEdges',edges,'FaceColor',colors(i,:));%sum of Steps(1:i) was added
hold on
end

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