How to fix "Undefined function 'sinc' for input arguments of type 'double'." Error

Question

Ege Tunç 2019-3-8

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/448976-how-to-fix-undefined-function-sinc-for-input-arguments-of-type-double-error

评论： Sean 2023-5-14

I found a code to use for my project far field diffraction generator however, I got an error called, Undefined function 'sinc' for input arguments of type 'double'.

How can i fix this?

Here is my code:

%------------------------------------------------------------------------
%-----Fraunhofer diffraction from a rectangular aperture-----------------
%------------------------------------------------------------------------
clc
close all
clear all
%------------------------------------------------------------------------
lambda=500e-9; k=(2*pi)/lambda; % wavelength of light in vaccuum
a=1e-6; b=1e-6; % dimensions of diffracting rectangular aperture
                % a is along Z and b is along Y
Io=100.0; % relative intensity
R=1.0e-3; % distance of screen from aperture
Y=(-0.25e-2:1e-5:0.25e-2); Z=Y ; % coordinates of screen
beta=k*b*Y/(2*R*pi);alpha=k*a*Z./(2*R*pi); % intermediate variable
 % diffracted intensity
for i=1:length(Y)
    for j=1:length(Z)
I(i,j)=Io.*((sinc(alpha(j)).^2).*(sinc(beta(i))).^2);
    end
end
%------------------------------------------------------------------------
   
 figure(1)
 imshow(I)
 title('Fraunhofer Diffraction','fontsize',14)
 fh = figure(1);
 set(fh, 'color', 'white'); 
 
 %------------------------------------------------------------------------

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Answer 1

KALYAN ACHARJYA 2019-3-8

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/448976-how-to-fix-undefined-function-sinc-for-input-arguments-of-type-double-error#answer_364440

编辑：KALYAN ACHARJYA 2019-3-8

在 MATLAB Online 中打开

I didnot find any error, when I run the code in my system (2015b)

clc;
clear all;
close all;
lambda=500e-9; k=(2*pi)/lambda; % wavelength of light in vaccuum
a=1e-6; b=1e-6; % dimensions of diffracting rectangular aperture
                % a is along Z and b is along Y
Io=100.0; % relative intensity
R=1.0e-3; % distance of screen from aperture
Y=(-0.25e-2:1e-5:0.25e-2); Z=Y ; % coordinates of screen
beta=k*b*Y/(2*R*pi);alpha=k*a*Z./(2*R*pi); % intermediate variable
 % diffracted intensity
for i=1:length(Y)
    for j=1:length(Z)
I(i,j)=Io.*((sinc(alpha(j)).^2).*(sinc(beta(i))).^2);
    end
end
%------------------------------------------------------------------------
 figure(1)
 imshow(I)
 title('Fraunhofer Diffraction','fontsize',14)
 fh = figure(1);
 set(fh, 'color', 'white'); 
 
 %------------------------------------------------------------------------
    

3 个评论
显示 1更早的评论隐藏 1更早的评论

Steven Lord 2019-3-8

The sinc function is defined in Signal Processing Toolbox (for numeric arrays) and Symbolic Math Toolbox (for symbolic arrays.) You didn't have Signal Processing Toolbox installed before but now you do.

Sean 2023-5-14