could you please convert it into a loop
显示 更早的评论
very simple logic but im not getting
n=4
K = [ 1, 2; 3, 4]
K1=zeros(n+1);
K1([1 2],[1 2])=K
K2=zeros(n+1);
K2([2 3],[2 3])=K
K3=zeros(n+1);
K3([3 4],[3 4])=K
K4=zeros(n+1);
K4([4 5],[4 5])=K
L=K1+K2+K3+K4;
how to convert this into loop where we can add more Kn matrices
2 个评论
"how to convert this into loop where we can add more Kn matrices"
Do NOT do that. Dynamically accessing variable names is one way that beginners force themselves into writing slow, complex, buggy code that is hard to debug. Read this to know why:
Indexing is neat, simple, and very efficient. You should use indexing, e.g. with a cell array or an ND numeric array.
page vnky
2019-3-9
采纳的回答
Guillaume
2019-3-10
In addition to what Stephen said, it's very easy to create your L for any n, without even a loop:
K = [1 2; 3 4];
n = 5;
L = toeplitz([trace(K), K(2, 1), zeros(1, n-2)], [trace(K), K(1, 2), zeros(1, n-2)]);
L([1, end]) = K([1, end])
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