Removing zeros from start of an array and inserting them at the end of same array

2 次查看(过去 30 天)
Let say I have an array
A = [ 0 0 0 0 1 2 3 4 5 6 7 8 9 0 0 0 0 ]
I would like to know wheter is there any way to move starting four zeros to the end of same array A.
The result should be
Result = [ 1 2 3 4 5 6 7 8 9 0 0 0 0 0 0 0 0 ]
Now, in this example there were only four zeros. I do have arrays which have more than 4 zeros.
Thanks

采纳的回答

Alex Mcaulley
Alex Mcaulley 2019-3-13
Try this:
A = [0 0 0 0 1 2 3 4 5 6 7 8 9 0 0 0 0];
idx = find(A>0,1);
B = [A(idx:end),zeros(1,idx-1)]
  3 个评论
Shahab Khan
Shahab Khan 2019-3-13
Thank you, actually i figured that out myself so i deleted the question. But anyway Thanks alot.

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更多回答(2 个)

Matt J
Matt J 2019-3-13
编辑:Matt J 2019-3-13
n=find(A,1);
Result=circshift(A,1-n);

Sheng Chen
Sheng Chen 2019-3-13
Try this
A = [ 0,1,0,3,12];
idx = 1;
for j = 1 : numel(A)
if A(j) ~= 0
% swap A(j) and A(idx)
A([j idx]) = A([idx j]);
idx = idx + 1;
end
end

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