find and omit element from array
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vv=(1:100)'
A=[3;8;21;44;60;79;99]
f_vv=find(vv==A);
vv(reshape(f_vv,length(f_vv),1))=[];
I got this error
Dimensions of arrays being concatenated are not consistent.
采纳的回答
madhan ravi
2019-3-14
编辑：madhan ravi
2019-3-14
21;44
% ^
vv(ismember(vv,A))=[]
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madhan ravi
2019-3-14
Alternatively;
vv(~ismember(vv,A))
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