Undefined operator '*' for input arguments of type 'function_handle'.

Question

Akshay Pratap Singh 2019-3-15

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/450210-undefined-operator-for-input-arguments-of-type-function_handle

评论： Steven Lord 2019-3-15

i wrote a following code. every thing is right but it shows error" Undefined operator '*' for input arguments of type 'function_handle'.

clear all

clc

syms x

h=4;

q=100;

delta=26;

phi=39;

kh=0;

kv=0;

psi=atan(kh/(1-kv));

da1=delta*(pi/180); pha1=phi*(pi/180);

m=pha1+da1;

b=pha1-psi;

c=psi+da1;

gma=18.4; nq=2*q/(gma*(x));

delta=26;

phi=39;

lam=0;

A=lam*nq/(1+nq);

alphac=atan((sin(m)*sin(b)+(sin(m)^2+sin(b)^2+sin(m)*cos(m)*sin(b)*cos(b)+A*cos(c)*cos(m)*sin(b))^0.5)/(A*cos(c)+sin(m)*cos(b)));

w=0.5*gma*(x)^2*(1/tan(alphac));

B=(x)*((1/tan(alphac))-lam);

ka1=((1+nq)*(1-A*tan(alphac))*(cos(b)-(sin(b)/tan(alphac))))/(cos(psi)*(cos(m)+tan(alphac)*sin(m)))

wt=w+q*B;

pa1 = matlabFunction(0.5*gma*x^2*ka1);

x=0:0.1:5;

R=(wt*(1-kv)-pa1*sin(da1))/cos(alphac-pha1);

za1=(0.5*R*cos(pha1)*(x/sin(alphac))-q*B*(lam*x+0.5*B)-(1/6)*(1/tan(alphac))*(gma/tan(alphac))*x^3)/(pa1*cos(da1))

plot(za1(x),x)

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Answer 1

Alex Mcaulley 2019-3-15

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https://ww2.mathworks.cn/matlabcentral/answers/450210-undefined-operator-for-input-arguments-of-type-function_handle#answer_365511

编辑：Alex Mcaulley 2019-3-15

在 MATLAB Online 中打开

You have some mix between symbolic functions and function handles. You need to choose one strategy. Try the following code, which uses only symbolic functions:

syms x
h=4;
q=100; 
delta=26;
phi=39;
kh=0;
kv=0;
psi=atan(kh/(1-kv));
da1=delta*(pi/180);  pha1=phi*(pi/180);
m=pha1+da1;
b=pha1-psi;
c=psi+da1;
gma=18.4;   nq=2*q/(gma*(x));
delta=26;
phi=39;
lam=0;
A=lam*nq/(1+nq);
alphac=atan((sin(m)*sin(b)+(sin(m)^2+sin(b)^2+sin(m)*cos(m)*sin(b)*cos(b)+A*cos(c)*cos(m)*sin(b))^0.5)/(A*cos(c)+sin(m)*cos(b)));
w=0.5*gma*(x)^2*(1/tan(alphac));
B=(x)*((1/tan(alphac))-lam);
ka1=((1+nq)*(1-A*tan(alphac))*(cos(b)-(sin(b)/tan(alphac))))/(cos(psi)*(cos(m)+tan(alphac)*sin(m)))
wt=w+q*B;
pa1 = (0.5*gma*x^2*ka1); %changed
% x=0:0.1:5; %changed
R=(wt*(1-kv)-pa1*sin(da1))/cos(alphac-pha1);
za1=(0.5*R*cos(pha1)*(x/sin(alphac))-q*B*(lam*x+0.5*B)-(1/6)*(1/tan(alphac))*(gma/tan(alphac))*x^3)/(pa1*cos(da1))
   
fplot(za1,[0,5]) %changed

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Steven Lord 2019-3-15

在 MATLAB Online 中打开

Alternately if you want to use just function handles, you can't perform arithmetic with the function handles themselves but you can perform arithmetic on the values you receive when you evaluate the function handle.

f1 = @sin;
f2 = @cos;
x = 0:0.05:2*pi;
% Add the results of evaluating f1 and f2
willWork = @(x) f1(x)+f2(x);
figure
plot(x, willWork(x))
title('Will work')
% Try to add f1 and f2
willNotWork = @(x) f1+f2;
figure
plot(x, willNotWork(x)) % This line will error so ...
title('This line of code won''t be executed')