Create cell array from 00.00 to 23.59

2019 3 15
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更新时间：2019 3 15
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Hi everyone,
i need to create a cell array containing time values from 00.00 to 23.59 with a step of 1 minute.
00.00
00.01
00.02
..
00.59
01.00
01.01
..
..
23.59
Just to explain it better,
t_iniz_proc=datetime(2018,2,5,0,0,0);
t_end_proc=datetime(2018,2,5,23,59,0);
DataArray=(t_iniz_proc:minutes(1):t_end_proc)'
i need something like that but i don't want to include the data, just the time in format 'hh.mm'
Can anyone help me?
Thanks a lot!
Fabio

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KALYAN ACHARJYA
KALYAN ACHARJYA 2019-3-15
With a step of 1 minute....means?
Fabio Pulcini
Fabio Pulcini 2019-3-15
each time in the array should be 1 minute later than the previous one.
KALYAN ACHARJYA
KALYAN ACHARJYA 2019-3-15
That menas 0.00 >>i min Gap>>0.01>>1 Min wait.....upto 23.59
Is this you are asking, if yes then it takes much longer time to exucates..near about 2500 min??
Confirm?
Fabio Pulcini
Fabio Pulcini 2019-3-15
no i don't need to pause the code.
I must create an array containing a time sequence that starts at midnight (00.00) of a not specified day and ends at 23.59 of that day. So that i can see each time minute by minute.

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KSSV
KSSV 2019-3-15

0 个投票

t = 00.00:0.01: 23.59 ;

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KALYAN ACHARJYA
KALYAN ACHARJYA 2019-3-15
编辑：KALYAN ACHARJYA 2019-3-15
@Time sir?
I dont undestand the logic of the question, Is he asking this one?
for i=2:iter %iter value so that last cell element reached 23.59
a{i}=a{i-1}+0.01;
pause(n); % Pause sec n
end
a=a';
Fabio Pulcini
Fabio Pulcini 2019-3-15
Thanks for the answer, but it generates an array containing values with 2 decimals till .99.
I need a time array, minute by minute from midnight to 23.59 h.
KSSV
KSSV 2019-3-15
t0= hours(00.00) ;
t1 = hours(23.59) ;
t = t0:hours(0.01):t1
madhan ravi
madhan ravi 2019-3-15
编辑：madhan ravi 2019-3-15
it's a duration array not a time array
KSSV
KSSV 2019-3-15
So what? I gave two options..let the user decide what he wants....nothing is going to harm with that.

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Steven Lord
Steven Lord 2019-3-15

0 个投票

minutesAfterMidnight = minutes(0):minutes(1):(hours(24)-minutes(1));
minutesAfterMidnight.Format = 'hh:mm';
firstTen = minutesAfterMidnight(1:10)
lastTen = minutesAfterMidnight(end-9:end)
You can add this to a datetime when or if you need times during a day.
minutesOfToday = datetime('today')+minutesAfterMidnight;
twoThirtyNineAM = minutesOfToday(2*60+40)
I added 40 instead of 39 when extracting 2:39 AM from minutesOfToday because 00:00 is element 1 of minutesAfterMidnight. Don't get caught by an off by one error.

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