Function behaves normally except when being called by another function

2 次查看（过去 30 天）
Abdolkarim Mohammadi
回答： Abdolkarim Mohammadi 2019-3-15
I am writing a code to evaluate the fitness function for evolutionary optimization purposes. The fitness function for the feasible points are their objective function and for the infeasible points is the maximum of the objective function value of the feasible points plus the maximum constraint violation of the infeasible points.
When I call the function solely to evaluate the fitness function, it works properly and returns correct outputs. But when being called from the main function of the optimization algorithm, it throws error:
The logical indices in position 1 contain a true value outside of the array bounds.
It also works fine in debugger mode. Part of the fitness function code is as follows:
InfeasibleSolutions = ...
LinearConstraintViolation | ...
lbConstraintViolation | ...
ubConstraintViolation | ...
NonlinearConstraintViolation;
FeasibleSolutions = ~InfeasibleSolutions;
ObjectiveFunctionValues = zeros(options.PopulationSize,1);
ObjectiveFunctionValues(FeasibleSolutions,:) = ...
fun(x(FeasibleSolutions,:)); % error is thrown from this line
MaximumObjectiveFunctionValue = max(ObjectiveFunctionValues);
The problem lies in logical indexing but I was not able to figure it out.
  2 个评论
dpb
dpb 2019-3-15
Looks like you created a logical vector then tried to use that as a logical addressing vector...but not sufficient information provided to tell for certain.
Set a breakpoint and use the debugger to track down your logic (so to speak :) ) error...
dpb
dpb 2019-3-15
编辑：dpb 2019-3-15
"It also works fine in debugger mode. ..."
Excepting for the fact it doesn't or you wouldn't have posted the problem. :)
dbstop on error
then start the command that generates the error.
You have still not provided nearly enough to be able to have any clue as to what any of the intermediate variables really are and not even the actual error in context so we can see what diagnostic information ML provided...
We can't debug by divining...

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Abdolkarim Mohammadi
Sorry dpb, it was my fault. The fitness function is called more than one time in the main algorithm, the last of which passes a smaller population than normal iterations and the fitness function was not able to handle the difference. Thanks for your rapid response.

类别

在 Help Center 和 File Exchange 中查找有关 Choose a Solver 的更多信息

标签

产品


版本

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by