How do I find closest values between 2 matrices?

2019 3 20
2 个回答
回答已采纳
更新时间：2019 3 20
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0 个投票

Lets say I have defined values like this:
true_ang = [-40 -20];
After passing through an algorithm, my output are polynomial roots such as this:
rts = roots(cc)
rts = 6×1 complex
-0.048729197855492 - 1.282493377891869i
-0.029583698890964 - 0.778607069086665i
0.409971042365044 + 0.917186264825464i
0.406190666466556 + 0.908728816636128i
-0.461769455823652 + 0.941122806650886i
-0.420194118738174 + 0.856388969382348i
This is followed by converting to angle form:
all_angs = -asin(angle(rts)/pi)*180/pi
all_angs = 6×1
30.803049614608504
30.803049614608490
-21.481431164796401 (this)
-21.481431164797179
-40.180359320706906 (this)
-40.180359320706934
My question is, how do I automatically obtain the closest values from all_angs to true_ang (which I've denoted at the sideas "this")? Note that the order of the results can be random.

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 采纳的回答

KSSV
KSSV 2019-3-20

0 个投票

Read about knnsearch
true_ang = [-40 -20];
all_angs = [ 30.803049614608504
30.803049614608490
-21.481431164796401
-21.481431164797179
-40.180359320706906
-40.180359320706934] ;
idx = knnsearch(all_angs,true_ang') ;
all_angs(idx)

更多回答（1 个）

Stephen23
Stephen23 2019-3-20
编辑：Stephen23 2019-3-20

0 个投票

Using basic MATLAB only (i.e. without knnsearch from the Statistics Toolbox):
>> true_ang = [-40,-20];
>> all_angs = [30.803049614608504,30.803049614608490,-21.481431164796401,-21.481431164797179,-40.180359320706906,-40.1803
59320706934];
>> [~,idx] = min(abs(true_ang - all_angs(:)),[],1);
>> all_angs(idx)
ans =
-40.180359320706906 -21.481431164796401

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