How to create a matrix using conditional statements in a loop based in another matrix

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Rachel Sabioni
Rachel Sabioni 2019-3-20
评论： Andrei Bobrov 2019-10-10
Hello,
I have a matrix and I want to generate another matrix according to their elements using a loop.
If one ore more elements of a row is ==0 the correspondent row in the new matrix need to be 0.
If not, it needs to be the sum of the elements in the row.
Comb = % The initial matrix
0 0
4.303 0
2.68 0
0 1.705
4.303 1.705
2.68 1.705
% I need this output:
H = [0
0
0
0
6.008
4.385]
I started with this loop:
for i = 1:size(Comb, 1)
for j = 1:size(Comb, 2)
x = (sum(Comb'))'
if abs(Comb(i,j)) == 0
end
end
end
But it gives that:
x =
0
4.303
2.68
1.705
6.008
4.385
I do not know what insert on the if to display zeros when one element of the row is equal to zero.
Could you help me ?
Thans in advance !

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2019-3-20
H = all(Comb,2).*sum(Comb,2);

更多回答（2 个）

madhan ravi
madhan ravi 2019-3-20
编辑：madhan ravi 2019-3-20
H=zeros(size(Comb,1),1);
idx=any(Comb,2);
H(idx)=sum(Comb(idx,:),2)
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Joel Newton
Joel Newton 2019-10-10
编辑：Joel Newton 2019-10-10
Hi, i wish to make a new matrix from the one below such that if the difference between elements in the second and third row is plus or minus 2 return a value of the mid point in each element of the new matrix. if the difrrence is more than 2 then keep the values from the old matrix in the new matrix.
orginal data =
1 1 1 1
10 10 10 9
14 11 14 11
new matrix should look like this =
1 1 1 1
10 10.5 10 10
14 10.5 14 10
my data set has multiple rows of this 3 block of values (if that makes sense), how do I then iterate down for the rest of the data?
Thanks!

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