How can i store values calculated in my loop

Question

fatihveysel nurcin 2019-3-20

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评论： fatihveysel nurcin 2019-3-20

Here is my code, i managed to do the operation however i can't store each column, what i get is only result of latest column, In this code, first element of column is checked if its less than 10, if yes then element is replaced by zero, code will keep checking elements of column and replace them by zero until it reaches to number 10;

However; I can't store all the columns, only last column is stored, how can store all the columns that i can reconstruct the new matrix;

X1 is the new matrix

X = [9 20 15 9 10 5;5 20 5 20 15 3;15 29 39 49 5 10];
[rows columns depth]=size(X);
for r=1:columns; % search for each column
    
    X1=X(:,r); %X1 is going to be new matrix
    for k=1:3 %k will help me to go through each element in column
    if X1(k)<10 % if first element is less than 10, replace it by 0 till 
        % i find the number which equal or higher than 10
      
         X1(k)=0;
    else
        break % if number is already more than 10, don't search for other
        % element in the column, switch to next column
         
    end
   
    end
  
end

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Answer 1

Star Strider 2019-3-20

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在 MATLAB Online 中打开

I am not certain what you are doing. One option is to create a second matrix (‘X2’ here), and store the results in it:

X = [9 20 15 9 10 5;5 20 5 20 15 3;15 29 39 49 5 10];
[rows columns depth]=size(X);
X2 = zeros(size(X));
for r=1:columns;
    X1=X(:,r);
    for k=1:3
        if X1(k)<10
            X1(k)=0;
        else
            break
        end
    end
    X2(:,r) = X1;
end

producing:

X2 =
  20    15     0    10     0
  20     5    20    15     0
  29    39    49     5    10

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fatihveysel nurcin 2019-3-20

thank you so much, i appreciate it

Star Strider 2019-3-20

As always, my pleasure.

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Answer 2

Andrei Bobrov 2019-3-20

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https://ww2.mathworks.cn/matlabcentral/answers/451246-how-can-i-store-values-calculated-in-my-loop#answer_366459

编辑：Andrei Bobrov 2019-3-20

在 MATLAB Online 中打开

X = [9 20 15 9 10 5;5 20 5 20 15 3;15 29 39 49 5 10];
[rows, columns]=size(X);
for r=1:columns
    for k=1:3
        if X(k,r)<10
            X(k,r)=0;
        else
            break
        end
    end
end