confusion related to 'for' loop.

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parag gupta
parag gupta 2019-3-20
回答： Steven Lord 2019-3-20
epsilon = 2
p = cell(1,8);
for i = 1:8
p{i} = epsilon
end
How to edit this code so that I can get p{1} = epsilon,p{2} = epsilon ^2 ,p{2} = epsilon ^3 .......
i.e i want p{1} = 2,p{2} = 4, p{3} =8.....
Thanks

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采纳的回答

madhan ravi
madhan ravi 2019-3-20
p = num2cell(2.^(1:8))
  1 个评论
madhan ravi
madhan ravi 2019-3-20
In your loop you just had to add
p{i} = epsilon^i
but you can straight away use the method in the answer.

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更多回答（1 个）

Steven Lord
Steven Lord 2019-3-20
Do you need the elements in a cell array, or is having them in a regular vector sufficient?
epsilon = 2;
thepowers = 1:8;
p = epsilon.^thepowers
If you're preparing for epsilon being a vector or matrix in the future, you can still use this technique, taking advantage of implicit expansion which is a generalization of scalar expansion. It just gets a little more complicated for matrices or N-dimensional arrays.
epsilon = [1; 2; 3; 4];
thepowers = 1:8;
p2 = epsilon.^thepowers
For a matrix M, you want thepowers to be a 3-dimensional array.
epsilon = magic(4);
thepowers = reshape(1:8, 1, 1, []) % or
thepowers = reshape(1:8, [1 1 8])
p3 = epsilon.^thepowers

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