How to write it in a loop?

2019 3 20
1 个回答
更新时间：2019 3 21
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a = 2
b = 3
p1(1) = a.b
p1(2) = a.b^2
p2(1) = a^2.b
p2(2) = a^2.b^2
.......i.e pi(j) = 2^i * 3^j where i from 1 to 4 and j from 1 to 5
Could someone please tell how to write this in a 'for' loop?

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回答（1 个）

Walter Roberson
Walter Roberson 2019-3-20

0 个投票

Hint:
Q17(1) = 18.5 - 82/19;
for K = 2 : 157
Q17(K) = Q17(K-1) + 82/19;
end
is equivalent to Q17(K) = 18.5 + 82/19*K

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parag gupta
parag gupta 2019-3-20
编辑：parag gupta 2019-3-20
A = zeros(4,5);
for i = 1:4
for j = 1:5
A(i,j) = 2^i*3^j
end
end
I thought to write like this.Is this wrong?
Walter Roberson
Walter Roberson 2019-3-21
Looks plausible.

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