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parfor loop , how should i use

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Hassan
Hassan 2019-3-22
关闭： MATLAB Answer Bot 2021-8-20
Hi,
this is part of my code, it is my frist time to use par for.
the first question, how to fix this error such that The variable Evaluation in a parfor cannot be classified.
second shoud i use parfor loop for eac for loop or that one time as my code?
Thanks in advance.
parfor i=1:iteration
for k=1:swarm_size
zz=1;
for j=1 :centers
[fbest,best]=min(Evaluation);
gbest= swarm(best,:);
new_pos =swarm(k,:);
v(k,zz:zz+1)=v(k,zz:zz+1)+c1*rand*(Pbest(k,zz:zz+1)-swarm(k,zz:zz+1))+c2*rand*(gbest(1,zz:zz+1)-swarm(k,zz:zz+1));
new_pos(1,zz:zz+1)=swarm(k,zz:zz+1)+v(k,zz:zz+1);
zo=1; lo=1;
for Io=1: centers
C3C(:,Io) = f(Invpoints(:,1), new_pos(1,zo),Invpoints(:,2), new_pos(1,zo+1));
zo=zo+2;
end
fnewpos= sum(min(C3C,[],2));
for go=1: centers
C4C(:,go) = f(Invpoints(:,1), swarm(k,lo),Invpoints(:,2), swarm(k,lo+1));
lo=lo+2;
end
fswarm = sum(min(C4C,[],2));
zz=zz+2;
end
end
min(Evaluation)
end
  16 个评论
显示 14更早的评论
Hassan
Hassan 2019-3-25
Swarm Size=100
Iterations = 100
Dimensions = 5 : 100
Walter Roberson
Walter Roberson 2019-3-25
I am not sure what Dimensions corresponds to in your code?
What kind of value does centers have?
Your code appears to run j=1:centers and within that loop runs for Io = 1:centers, and also for go=1:centers . That suggests a run time on the order of swarm_size * centers^2 -- or possibly more as it is not clear whether f is a function or a 4D array being indexed.
Your code would really benefit from comments; it is difficult to understand what you are doing and why.

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