invalid syntax at '=' . A '(' might be missing a closing ')'
显示 更早的评论
The error is at line 14 and 26
switch nargin
case 0
disp('Non ci sono stati input per la funzione!')
case 1
if (f = 0)
disp('Non hai inserito correttamente la funzione la funzione')
end
case 2
if(~isscalar(xo) || isinteger(xo))
disp('Mammt')
end
case 3
if(~isscalar(xo) || isinteger(xo)) % anche se ci sta un altro controllo che nello non vuole dirmi
disp('A')
end
case 4
if(~isinteger(NMAX) || NMAX = 0 || ischar(NMAX))
disp('A pecrrrr, cioè nmax non va bene')
end
end
采纳的回答
if (f == 0)
and same thing in this line
if(~isinteger(NMAX) || NMAX == 0 || ischar(NMAX))
1 个评论
Guillaume
2019-3-29
Note that matlab is not C, there is no need to enclose a conditional statement in (), so
if f == 0
if ~isinteger(NMAX) || NMAX == 0 || ischar(NMAX)
Note that isinteger check that the type is integer not that the values are integer,
>> isinteger(1) %return false, since double is not an integer type
ans =
logical
0
>> isinteger(uint8(1)) %return true, the type is integer
ans =
logical
1
I suspect that you meant to test if the value was integer, not the type.
Also note that the ischar(NMAX) is redundant, if NMAX is char, it will have failed the ~isinteger test.
validateattributes(f, {'numeric'}, {'nonzero', 'scalar'});
validateattributes(NMAX, {'numeric'}, {'integer', 'nonzero', 'scalar'})
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