How to save output from loop's eteration into a new matrix.

Question

Areeb Siraj 2019-3-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/453439-how-to-save-output-from-loop-s-eteration-into-a-new-matrix

评论： Areeb Siraj 2019-3-31

采纳的回答： Rebecca Cleveland Stout

% for I quad

%%co-ordinadets of n and e

n = [-0.557 0.577 0.577 -0.577]; e = [-0.577 -0.577 0.577 0.577];

%%co-ordinadets of x and y

for j=10:10:100 for i=10:10:100 x = [i-10 i i i-10]; y = [j-10 j-10 j j];

A = -0.25*(1-n); B = -0.25*(1-e); C = 0.25*(1-n); D = -0.25*(1+e); E = 0.25*(1+n); F = 0.25*(1+e); G = -0.25*(1+n); H = 0.25*(1-e);

Ia = (A(1,1)*x(1,1)) + (C(1,1)*x(1,2)) + (E(1,1)*x(1,3)) + (G(1,1)*x(1,4)); Ja = (B(1,1)*x(1,1)) + (D(1,1)*x(1,2)) + (F(1,1)*x(1,3)) + (H(1,1)*x(1,4)); Ka = (A(1,1)*y(1,1)) + (C(1,1)*y(1,2)) + (E(1,1)*y(1,3)) + (G(1,1)*y(1,4)); La = (B(1,1)*y(1,1)) + (D(1,1)*y(1,2)) + (F(1,1)*y(1,3)) + (H(1,1)*y(1,4));

% M is jacobian matrix

Ma = [Ia Ja; Ka La]; Na = inv(Ma'); %Mi' = transpose of Jacobian matrix P1a = Na*[A(1,1); B(1,1)]; P2a = Na*[C(1,1); D(1,1)]; P3a = Na*[E(1,1); F(1,1)]; P4a = Na*[G(1,1); H(1,1)];

Qa = [P1a(1,1) 0 P2a(1,1) 0 P3a(1,1) 0 P4a(1,1) 0; 0 P1a(2,1) 0 P2a(2,1) 0 P3a(2,1) 0 P4a(2,1); P1a(2,1) P1a(1,1) P2a(2,1) P2a(1,1) P3a(2,1) P3a(1,1) P4a(2,1) P4a(1,1)]; S = 180; %% value of E = 180 N/mm2 for steel T = 78; %% value of G = 78 N/mm2 for steel U = 34; %% value of poison's ratio V = [(1/S) (-U/S) 0; (-U/S) (1/S) 0; 0 0 (1/T)]; W = inv(V); X1 = 1; %% weighted fucntion w1 X2 = 1; %% weighted fucntion w2 t = 1; %% thickness X3a = det(Ma); %% determinant of jacobian matrix Ya = X1*X2*Qa'*W*Qa*t*X3a;

% for II quad

Ib = (A(1,2)*x(1,1)) + (C(1,2)*x(1,2)) + (E(1,2)*x(1,3)) + (G(1,2)*x(1,4)); Jb = (B(1,2)*x(1,1)) + (D(1,2)*x(1,2)) + (F(1,2)*x(1,3)) + (H(1,2)*x(1,4)); Kb = (A(1,2)*y(1,1)) + (C(1,2)*y(1,2)) + (E(1,2)*y(1,3)) + (G(1,2)*y(1,4)); Lb = (B(1,2)*y(1,1)) + (D(1,2)*y(1,2)) + (F(1,2)*y(1,3)) + (H(1,2)*y(1,4));

% M is jacobian matrix Mb = [Ib Jb; Kb Lb]; Nb = inv(Mb'); %Mi' = transpose of Jacobian matrix P1b = Nb*[A(1,2); B(1,2)]; P2b = Nb*[C(1,2); D(1,2)]; P3b = Nb*[E(1,2); F(1,2)]; P4b = Nb*[G(1,2); H(1,2)];

Qb = [P1b(1,1) 0 P2b(1,1) 0 P3b(1,1) 0 P4b(1,1) 0; 0 P1b(2,1) 0 P2b(2,1) 0 P3b(2,1) 0 P4b(2,1); P1b(2,1) P1b(1,1) P2b(2,1) P2b(1,1) P3b(2,1) P3b(1,1) P4b(2,1) P4b(1,1)]; X3b = det(Mb); %% determinant of jacobian matrix Yb = X1*X2*Qb'*W*Qb*t*X3b;

% for III quad

Ic = (A(1,3)*x(1,1)) + (C(1,3)*x(1,2)) + (E(1,3)*x(1,3)) + (G(1,3)*x(1,4)); Jc = (B(1,3)*x(1,1)) + (D(1,3)*x(1,2)) + (F(1,3)*x(1,3)) + (H(1,3)*x(1,4)); Kc = (A(1,3)*y(1,1)) + (C(1,3)*y(1,2)) + (E(1,3)*y(1,3)) + (G(1,3)*y(1,4)); Lc = (B(1,3)*y(1,1)) + (D(1,3)*y(1,2)) + (F(1,3)*y(1,3)) + (H(1,3)*y(1,4));

% M is jacobian matrix Mc = [Ic Jc; Kc Lc]; Nc = inv(Mc'); %Mi' = transpose of Jacobian matrix P1c = Nc*[A(1,3); B(1,3)]; P2c = Nc*[C(1,3); D(1,3)]; P3c = Nc*[E(1,3); F(1,3)]; P4c = Nc*[G(1,3); H(1,3)];

Qc = [P1c(1,1) 0 P2c(1,1) 0 P3c(1,1) 0 P4c(1,1) 0; 0 P1c(2,1) 0 P2c(2,1) 0 P3c(2,1) 0 P4c(2,1); P1c(2,1) P1c(1,1) P2c(2,1) P2c(1,1) P3c(2,1) P3c(1,1) P4c(2,1) P4c(1,1)]; X3c = det(Mc); %% determinant of jacobian matrix Yc = X1*X2*Qb'*W*Qb*t*X3c;

% for IV quad

Id = (A(1,4)*x(1,1)) + (C(1,4)*x(1,2)) + (E(1,4)*x(1,3)) + (G(1,4)*x(1,4)); Jd = (B(1,4)*x(1,1)) + (D(1,4)*x(1,2)) + (F(1,4)*x(1,3)) + (H(1,4)*x(1,4)); Kd = (A(1,4)*y(1,1)) + (C(1,4)*y(1,2)) + (E(1,4)*y(1,3)) + (G(1,4)*y(1,4)); Ld = (B(1,4)*y(1,1)) + (D(1,4)*y(1,2)) + (F(1,4)*y(1,3)) + (H(1,4)*y(1,4));

% M is jacobian matrix Md = [Id Jd; Kd Ld]; Nd = inv(Md'); %Mi' = transpose of Jacobian matrix P1d = Nd*[A(1,4); B(1,4)]; P2d = Nd*[C(1,4); D(1,4)]; P3d = Nd*[E(1,4); F(1,4)]; P4d = Nd*[G(1,4); H(1,4)];

Qd = [P1d(1,1) 0 P2d(1,1) 0 P3d(1,1) 0 P4d(1,1) 0; 0 P1d(2,1) 0 P2d(2,1) 0 P3d(2,1) 0 P4d(2,1); P1d(2,1) P1d(1,1) P2d(2,1) P2d(1,1) P3d(2,1) P3d(1,1) P4d(2,1) P4d(1,1)]; X3d = det(Md); %% determinant of jacobian matrix Yd = X1*X2*Qd'*W*Qd*t*X3d;

% equvalent matix Yeq = Ya + Yb + Yc + Yd; end end

This is my code and I want save output from loop's eteration in a matrix of size 80 by 80 for further formulation. Such that the first element of this new matrix is the first eteration of loop and so on.

3 个评论
显示 1更早的评论隐藏 1更早的评论

Areeb Siraj 2019-3-30

<<www-mathworks-com-matlabcentral-answers-uploaded_files-211221-Screenshot_2019-03-30-22-40-28-802_com-mathworks-matlabmobile.png>>

<<www-mathworks-com-matlabcentral-answers-uploaded_files-211222-Screenshot_2019-03-30-22-41-27-055_com-mathworks-matlabmobile.png>>

<<www-mathworks-com-matlabcentral-answers-uploaded_files-211223-Screenshot_2019-03-30-22-41-32-719_com-mathworks-matlabmobile.png>>

<<www-mathworks-com-matlabcentral-answers-uploaded_files-211224-Screenshot_2019-03-30-22-41-37-467_com-mathworks-matlabmobile.png>>

Pls help yourself

Jan 2019-3-30

编辑：Jan 2019-3-30

Seriously?

Do not overestimate the willingness of the forum to fix unreadable code, to guess the meaning of vague questions and to follow badly formatted links to not existing web pages. Of course there is no server called "www-mathworks-com-...", but it must be "www.mathworks.com/...".

TUTORIAL: how to ask a good question

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Rebecca Cleveland Stout 2019-3-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/453439-how-to-save-output-from-loop-s-eteration-into-a-new-matrix#answer_368260

在 MATLAB Online 中打开

Your code is quite hard to read, but generally, to save elements in a loop, you can do:

A = NaN*ones(80); % preallocate matrix where you want to save stuff
for k = 1:numel(A)
    % do your operations
    A(k) = result; % save your kth result to element k of the matrix
end